Scrabble score


#1



https://www.codecademy.com/en/courses/python-intermediate-en-rCQKw/1/3?curriculum_id=4f89dab3d788890003000096#


Oops, try again. Your function fails on scrabble_score("xenophobia"). It returns "23" when it should return "24".


what is wrong


def scrabble_score(text):
    score = {"a": 1, "c": 3, "b": 3, "e": 1, "d": 2, "g": 2, 
         "f": 4, "i": 1, "h": 4, "k": 5, "j": 8, "m": 3, 
         "l": 1, "o": 1, "n": 1, "q": 10, "p": 3, "s": 1, 
         "r": 1, "u": 1, "t": 1, "w": 4, "v": 4, "y": 4, 
         "x": 8, "z": 10}
    count = 0
    total = 0
    for x in score:
        if x in text.lower():
            total += score[x]
    return total    
print scrabble_score("word")


#2

you loop over score, why?


#3

under score not over score.


#4

i am asking you why you are looping over you score dictionary inside your function, can you explain me?


#5

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