Scrabble_score


#1


Hi,
Am I even close with this code?.


score = {"a": 1, "c": 3, "b": 3, "e": 1, "d": 2, "g": 2, 
         "f": 4, "i": 1, "h": 4, "k": 5, "j": 8, "m": 3, 
         "l": 1, "o": 1, "n": 1, "q": 10, "p": 3, "s": 1, 
         "r": 1, "u": 1, "t": 1, "w": 4, "v": 4, "y": 4, 
         "x": 8, "z": 10}
         
def scrabble_score(word):
    for i in word:
        if i == score:
            return sum(score[i])

print scrabble_score("pie")


#2

its a step in the right direction, here:

if i == score:

score is a dictionary, and i is a letter of word. A letter can't possible equal a dictionary. The exercise tells you that you can assume all inputs will be valid, so no need for the if condition

sum() calculates the sum of an iterable like a list, so you would need to make a list and append the score of i to the list and then take the sum() of the list

Post an updated version of your code if you need more help


#3

I done it with a different approach.
Thanks for help


#4

That is also fine, you are free to choice the approach you want. Good that you solved it :slight_smile:


#5