Scrabble_score: int object is not callable


#1



Oops, try again. Your function crashed on pie as input because your function throws a "'int' object is not callable" error.

The output 5 is being printed but the error "int object is not callable" is being displayed.


score = {"a": 1, "c": 3, "b": 3, "e": 1, "d": 2, "g": 2,
"f": 4, "i": 1, "h": 4, "k": 5, "j": 8, "m": 3,
"l": 1, "o": 1, "n": 1, "q": 10, "p": 3, "s": 1,
"r": 1, "u": 1, "t": 1, "w": 4, "v": 4, "y": 4,
"x": 8, "z": 10}

def scrabble_score(word):
    word = word.lower()
    s = 0
    for i in word:
        s+= score[i]
    return s

print scrabble_score('pie')


#2

your code is fine, try refreshing the page/different browser


#3

This topic was automatically closed 7 days after the last reply. New replies are no longer allowed.