scrabble_score help please!


#1

<PLEASE USE THE FOLLOWING TEMPLATE TO HELP YOU CREATE A GREAT POST!>

<Below this line, add a link to the EXACT exercise that you are stuck at.>

<In what way does your code behave incorrectly? Include ALL error messages.>
Here is the error: Your function fails on scrabble_score(“xenophobia”). It returns “23” when it should return “24”.
<What do you expect to happen instead?>
Please help! Thanks in advance!

```python

score = {“a”: 1, “c”: 3, “b”: 3, “e”: 1, “d”: 2, “g”: 2,
“f”: 4, “i”: 1, “h”: 4, “k”: 5, “j”: 8, “m”: 3,
“l”: 1, “o”: 1, “n”: 1, “q”: 10, “p”: 3, “s”: 1,
“r”: 1, “u”: 1, “t”: 1, “w”: 4, “v”: 4, “y”: 4,
“x”: 8, “z”: 10}

def scrabble_score(word):
total = 0
for key in score:
if key in str(word).lower() :
total = total + score[key]
return total

<do not remove the three backticks above>

#2

It’s only iterating over o once, so the score is off by 1. Try iterating the string, instead.

for key in str(word).lower():
    total += score[key]

#3

I’ve just finished this assignment and came here to look at alternative solutions… I tested my approach using the word “Xenophobia” too… what are the odds?! Hehe.