# Scrabble exercise - dictionary lesson

#1

I am stuck with the following exercise.

## Here’s my code

``````
letters = ["A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z"]
points = [1, 3, 3, 2, 1, 4, 2, 4, 1, 8, 5, 1, 3, 4, 1, 3, 10, 1, 1, 1, 1, 4, 4, 8, 4, 10]

letter_to_points ={letter:point for letter,point in zip(letters,points)}
letter_to_points[' '] = 0
print(letter_to_points)

def score_word(word):
point_total = 0
for char in word:
point_total += letter_to_points.get(char, 0)
return point_total

brownie_points = score_word('BROWNIE')
print(score_word('BROWNIE'))
``````

For the word BROWNIE it returns me 3 instead 15 but i don’t get the reason.

Can you help me on that?

Thanks

#2

the letter `b` is worth 3 points, so it seems your function only awards points for the first letter. How could that be? How could you verify this is the bug you have? Any ideas?

#3

Thank you @stetim94.
I noticed it seemed to consider just the first letter.
I cannot understand wher the bug is as the for the loop should iterate throughout all char in word

#4

So you have determined that the loop does not behave as expected. What could be a next step? You could use this tool:

http://www.pythontutor.com/visualize.html#mode=edit

to see where things go wrong.

#5