Rock, paper, scissors, lizard, spock, with fewer if statements

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/* This plays the game “rock, scissors, paper, lizard, Spock”, but has half the if statements in the CodeAcademy example. :slight_smile:
*/

#include
#include <stdlib.h>
#include

int main() {
//live long and prosper
int user = 0;
while (user != 6) {
srand (time(NULL));
int computer = rand() % 3 + 1;

    std::cout << "\n\n\n Want to play rock, paper, scissors, lizard, spock?\n";
    std::cout << "rock = 1\n";
    std::cout << "paper = 2\n";
    std::cout << "scissors = 3\n";
    std::cout << "Spock = 4\n";        //Sheldon's logic requires Spock to be 4 instead of 5.
    std::cout << "lizard = 5\n";
    std::cout << "quit = 6\n";
    std::cout << "shoot! ";

    std::cin >> user;

   if (user == 6) {
      std::cout << "\n\n GOODBYE! ";
      break;
    };

    std::cout << "\n The user chose " + std::to_string(user);
    std::cout << "\n The computer chose " + std::to_string(computer);
    std::cout << ("\n user: " + std::to_string(user) 
                + " computer: " + std::to_string(computer));
    
    if ((user < 1) || (user > 5)) {
      std::cout << "    Invalid Response\n";
    } else if (user == computer) {
      std::cout << "    It's a tie!\n";
    } else if (user > computer) {
        if ((user % 2) == (computer % 2)) {
          std::cout << "   You lose. :(\n";
        } else {
          std::cout << "    You win! :)\n";
        } 
    } else if((user % 2) == (computer % 2)) {
        std::cout << "   You win! :(\n";
    } else {
        std::cout << "   You lose. :)\n";
    } // end primary if

} // end while loop
} // end function

1 Like
2

Who wants to be the one to bash Spock with a rock? Better that the lizard dispatches him, no?