Rock Paper Scissors 8


#1



8. What if choice1 is scissors?


I can't figure out why I'm getting "Syntax error: missing before statement". I've tried everything to make this code work, but I can't find what's wrong. Any ideas?


var userChoice = prompt("Do you choose rock, paper or scissors?");
var computerChoice = Math.random();
if (computerChoice < 0.34) {
    computerChoice = "rock";
} else if(computerChoice <= 0.67) {
    computerChoice = "paper";
} else {
    computerChoice = "scissors";
} console.log("Computer: " + computerChoice);

var compare = function(choice1, choice2) {
    if(choice1 === choice2) {
        return "The result is a tie!";
    }
    else if(choice1 === "rock") {
        if(choice2 === "scissors") {
            return "rock wins";
        }
        else {
            return "paper wins"
        }
    }
    else if(choice1 === "paper") {
        if(choice2 === "rock") {
            return "paper wins"
        }
        else {
            return "scissors wins"
        }
    }
    else if(choice1 === "scissors") {
        if(choice2 === "paper") {
            return "scissors wins"
        }
        else (choice2 === "rock") {
            return "rock wins"
        }
    }
};
compare(userChoice,computerChoice);


#2

HI this part

else (choice2 === "rock") {
            return "rock wins"
        }

just remove the condition to the else statement


#3

Of course! That worked -- I don't know how I missed it. Thanks!