# RGB-HEX converter Break problems

#1

SyntaxError: 'break' outside loop
HELP ME!

``````def rgb_hex():
invalid_msg="This is ERROR!!!"
red = int(raw_input("Enter Red (R) value: "))
if (red<0 or red > 255):
print invalid_msg
return
green = int(input("Enter a Green (G) value: "))
if green < 0 or green > 255:
print invalid_msg
return
blue = int(input("Enter a Blue (B) value: "))
if blue < 0 or blue > 255:
print invalid_msg
return
val=(red<<16)+(green<<8)+blue
print "%s" %(hex(val)[2:]).upper()
def hex_rgb():
hex_val=raw_input("Enter the color(six hexadecimal digits): ")
if len(hex_val)!=6:
print "Invalid hexidecimal value. Try again."
return
else:
hex_val=int(hex_val,16)

two_hex_digits= 2**8

blue=hex_val % two_hex_digits
hex_val=hex_val>>8
green=hex_val % two_hex_digits
hex_val=hex_val>>8
red=hex_val % two_hex_digits

print "Red: %s Green: %s Blue: %s" % (red,green,blue)
def convert():
while True:
option = raw_input("Enter 1 to convert RGB to HEX. Enter 2 to convert HEX to RGB. Enter X to Exit: ")
if option=='1':
print "RGB to Hex..."
rgb_hex()
elif option == '2':
print "Hex to RGB..."
hex_rgb()
elif option == 'X' or option == 'x':
break
else:
print "Error"

convert()``````

#2

Hi, @ssaabbiirr ,

Increase the indentation of the entire `if`-`elif`-`else` structure in the `convert` function. It is not indented sufficiently to be part of the `while` loop.

#3

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