Review: Functions! Please check my code


#1

17/19 Review: Functions!

https://www.codecademy.com/courses/learn-python/lessons/functions/exercises/review-functions?action=lesson_resume

My code

def shout_down(s):
if shut_down(“yes”):
return "Shutting down"
elif shut_down(“no”):
return "Shutdown aborted"
else:
return “Sorry”

My error
File “python”, line 6
else:
^
SyntaxError: invalid syntax

Please help!


#2

-1 they are asking for shutdown
-2 Indentation is very IMPORTANT in Python…per level 4-spaces (do not use tabs)
-3 you should be checking the VALUE of s , but you are calling a FUNCTION…!!!

def shout_down(s):
		if shut_down("yes"):
  			return "Shutting down"
  		elif shut_down("no"):
  				return "Shutdown aborted"
				else:   <<<<<<<<wrong indentation !!!!!
          	                        return "Sorry"

I did not change the wrongs in your code
i only changed the indentation pattern !!!
should be something like

def shout_down(s):
    #4-spaces
    if shut_down("yes"):
        # extra 4-spaces
        return "Shutting down"
    elif shut_down("no"):
        return "Shutdown aborted"
    else:
        return "Sorry"

Please read the FUNCTION-talk

+++ function talk
Please read the Function talk
and concentrate on

  • parameter
  • parameter being a =local variable= within function body
  • argument
  • calling a function
  • usage of the return statement

the FUNCTION talk

def myFunc( param1, param2):
    # Begin of =myFunc= FUNCTION-BODY
    # this =myFunc= function- has 2 PARAMETERS param1 and param2
    # param1 and param2 PARAMETERS are used 
    # as -local- VARIABLES throughout the =myFunc= FUNCTION-BODY
    print( param1 + " and " + param2 )
    #End of =myFunc= FUNCTION-BODY

If you want to call/execute the myFunc function
you will have to add a pair of parentheses to myFunc
like
myFunc()
As the myFunc function was defined
as having 2 parameters
you have to provide 2 arguments
in our case 2 string VALUES “Alena” and "Lauren"
like
myFunc(“Alena”,“Lauren”)

some quotes from the outer-world:

argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block

OR

“parameters” are called “formal parameters”,
while “arguments” are called “actual parameters”.

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
++++ function with 1 parameter using return-statement

def myFunction( param1 ):
    # //Begin of =myFunction= FUNCTION-BODY
    # //=myFunction= function has 1 PARAMETER param1
    # //this param1 PARAMETER is used as a -local- VARIABLE
    # //throughout the =myFunction= FUNCTION-BODY
    return param1;
    # //End of FUNCTION-BODY

You have defined a myFunction function
which takes 1 parameter param1
this param1 parameter is used
as a variable throughout the =myFunction= FUNCTION-BODY.

If you want to call/execute this myFunction function
and this myFunction function was defined
as having 1 parameter param1
you will have to provide 1 argument
in our case a “number VALUE” 4
myFunction( 4 )

some quotes from the outer-world:

argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block

OR

“parameters” are called “formal parameters”,
while “arguments” are called “actual parameters”.

============================================

As you are using the return-statement in your myFunction function
you will only get a return-value no-display.
You can however capture this return-value in a variable
and then use the print-method to do a display.

theResult = myFunction( 4 )
print theResult

OR directly

print myFunction( 4 )

#3

How about this new one?

def shout_down(s):
    if s == "yes":
  	    return "Shutting down"
    elif s == "no":
        return "Shutdown aborted"
    else:
        return "Sorry"

There is no error message but below the console where I type Python it says “Did you create a function called shut_down?”


#4

you have

** shout_down **

and they ask

** shut_down **


#5

Thank you and i’m sorry.I’m very silly.


#6

Hi,

Please help me understand what is wrong with my code:

def shut_down(s):
if s==“yes”:
return "Shutting down"
elif s==“no”:
return "Shutdown aborted"
else:
return “Sorry”

The error message I am getting is :
File “python”, line 5
elif s==“no”:
^
SyntaxError: invalid syntax

I am stuck as I am unable to understand what is wrong with my ‘elif’ syntax.
Can somebody please help me figure this out?


#8

I was able to figure out and the code is running successfully now. It was an indentation error.

Sorry and thank you.


#9

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