# Reversed list

Hey. Could someone explain to me why this function isn’t working.

Its from the exercise

"Create a function named `reversed_list()` that takes two lists of the same size as parameters named `lst1` and `lst2` .

The function should return `True` if `lst1` is the same as `lst2` reversed. The function should return `False` otherwise.

For example, `reversed_list([1, 2, 3], [3, 2, 1])` should return `True`."

it works with:

``````if lst1[index] != lst2 [len(lst2-1-index]:
return False
``````

return True

But doesn’t work the other way. Why so?

Hey there and welcome to the forums

Might wanna look at the logic within your loop here, currently you say that `if` a condition is `True` than immediately `return` `True`. All this states is that the first elements to be compared are the same, What about the other elements in the list?

I’m assuming there was a typo here and you meant to have a parenthesis here:

``````if lst1[index] != lst2 [len(lst2)-1-index]:
^
return False
``````

This works because you only need one wrong pair to know the list isn’t reversed, the rest won’t matter.

2 Likes

If you wanted to finish with your original approach, this would have done it:

``````def reversed_list(lst1, lst2):
for index in range(len(lst1)):
if lst1[index] == lst2[len(lst2) - 1 - index]:
continue
else:
return False
return True

print(reversed_list([1,2,3], [3,2,1]))
print(reversed_list([1,5,3], [3,2,1]))
``````

`continue` allows it to finish the iterations of the for loop.