Return keyword


Here is my code:

    // Parameter is a number, and we do math with that parameter
    var timesTwo = function(number) {
        return number * 2;

    // Call timesTwo here!
    var newNumber = function(timesTwo)
   console.log( newNumber);


What is wrong: Oops, try again. You didn't call the timesTwo function!



### function with 1 parameter using return-statement

var myFunction = function( param1 ) {
       //Begin of FUNCTION-BODY
       //myFunction =function= has 1 PARAMETER param1
       //this param1 PARAMETER is used as a -local- VARIABLE
       //throughout the FUNCTION-BODY

      return param1;

      //End of FUNCTION-BODY

you have defined a myFunction function
which takes 1 parameter param1
this param1 parameter is used
as a variable throughout the FUNCTION-BODY.

If you want to call/execute this myFunction function
and this myFunction function was defined
as having 1 parameter param1
you will have to provide 1 argument
in our case a "number VALUE" 4
myFunction( 4 );

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**


**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**


As you are using the return-statement in your myFunction function
you will only get a return-value no-display.
You can however capture this return-value in a variable
and then use the console.log()-method to do a display.

var theResult = myFunction( 4 );
console.log( theResult );

OR directly

console.log( myFunction( 4 ) );



They want you to capture the return-Result into a variable newNumber
by assigning the outcome of calling the timeTwo function

var newNumber = timesTwo(2);
console.log( newNumber );