# Remove_duplicates

#1

Hi there!

I got a working solution (I feel), but the test is giving me the following error message:

Oops, try again. Your remove_duplicates modifies the list that was passed to it. [4, 5, 5, 4] was modified to [5]. Perhaps you should make a copy first!

I don't feel this is what I am doing, I am copying the original list in a new list I call 'result'.
If I try the code with a list myself, the answer seems to be right.

Of course there is another way to do this but I thought of this way myself and now I would like to know if I am wrong or not. Could you guys help me out?

Code:

``````def remove_duplicates(list):
result = list
for x in result:
test = x
for y in result:
if y == test:
result.remove(y)
return result

print remove_duplicates([1,1,2,2])``````

#2

this:

``result = list``

will not make a copy of the list, it just creates a variable which points to the original list. You could use a loop to append the items of list into result, or use the built in `list()` function

#3

You'll have to follow the tip from the exercise, it's pretty easy once you get a grasp of the requirement.

Here's what I did.

# Define the function to accept the duplicate number list

def remove_duplicates(duplicate_numbers):

# Then create an empty list, this is where you'll house the unique lis, i.e. no duplicates

``duplicate = []``

# Loop through the entered duplicate list and store the numbers in the list as number

``for number in duplicate_numbers:``

# Loop and compare all the numbers.

``    for i in duplicate_numbers:``

# Now check if the numbers are equal

``        if i == number:``

# If the number is equal, then check if it is present in your new list that holds unique item

``            if i not in duplicate:``

# If it's not present, then add it.

``````                duplicate.append(i)
return duplicate``````

print remove_duplicates([4,5,4,5])

Hope this helps.

#4

Thanks for the responses! I managed to finish this course

#5