# Remove duplicate

#1

``````def remove_duplicates(lits):
new_list = []
for x in lits:
if new_list==[]:
new_list.append(x)
continue
for y in new_list:
if x!=y:
new_list.append(x)

return new_list``````

# what is wrong with my code plz help

``Replace this line with your code.``

#2

this condition:

``if x!=y:``

won't work, its not only about succesive items which are the same.

if we have:

``[1,2,3,1]``

the result should be:

``[1,2,3]``

your code won't do this because the `1`'s are not next to each other, so your if condition never catches it

Maybe you should check the hint in the lesson?

#3

for y in new_list:
if x!=y:
new_list.append(x)
"""this part will iterate through the new list before appending in the new list so i think there is no chance of repetition of the numbers...."""

#4

i see where you are going. But that is not what is currently happening

What you want to do is use this loop to check if `x` is in new_list, if not, append to new_list, right?

currently, for each value (`y`) in new_list which doesn't equal `x`, we append `x` to new_list

#5

``````def remove_duplicates(lits):
c=0
new_list = []
for x in lits:
if new_list==[]:
new_list.append(x)
continue
for y in new_list:
if x!=y:
continue
else:
c+=1

if c==0:
new_list.append(x)

return new_list``````

#6

here:

``c=0``

could you explain why you placed `c=0` where you did?

it means that once a duplicate value is found in new_list, `c` will never be zero again, so all values after the first duplicate value won't be added

#7

This topic was automatically closed 7 days after the last reply. New replies are no longer allowed.