I’m a bit confused
We have variable “words” buy later in the loop we use “word”. Could you clarify please?
Actually the code works also if I use “words” everywhere so what is the difference?
I’m a bit confused
Alright, so “words” and “word” are used in two different ways.
“words” is the variable, “word” is the parameter. So let’s just for now change these words to better reflect their property.
words is now “variable”, word is not “parameter”
so with every parameter in variable “this” will happen. Maybe if you see it like that it’ll help you understand what’s going on
2 more questions:
- You say: words is now “variable”, word is not “parameter”. Is it correct? Or do you mean "… now “parameter”?
- Why that case if I code as follows it also works?
[quote] puts “Type your text”
puts “Word to redact”
words.each do |words|
if words != redact
print words + " "
else print "REDACTED "
words.each do |words| if words != redact print words + " " else print "REDACTED " end end
This is what you have.
But this is what I mean:
puts "Type your text" text=gets.chomp puts "Word to redact" redact=gets.chomp variable=text.split(" ") variable.each do |parameter| if parameter != redact print parameter + " " else print "REDACTED " end end
Don’t do this in your actual program, I’m just showing you what the computer sees so it’s more clear what you’re looking at
Would you mind if I give a small advise as I’m not native english speaker? It would be less confusing if the training program not allow to use “words” as a “parameter”. Or it’s not because of the soft?
One more question
As I understand parameter + " " adds spaces after each word. But how we add space after first word? For example I have a string “I love coding” and word “love” was redacted to "REDACTED ". That case space added after “REDACTED” but what about space after “I”?
else print "REDACTED " ^
Just add a space there
The thing is there is a space without adding adding a space into "REDACTED ")))
But I’ve got your idea)