Reading between the lines


my_file = open("text.txt","r")
print my_file.readline()


why it is showing this error

Traceback (most recent call last):
File "python", line 1, in
IOError: [Errno 2] No such file or directory: 'text.txt'

Replace this line with your code.

Error in the open() function


my_file = open("text.txt","r")

you are trying to open an existing read modus.....
If you use following code
you will see which files are available....

import os
print "==show us the existing files =="
files = [f for f in os.listdir('.') if os.path.isfile(f)]
for f in files:
    print str(f)


With following code
you will do a test of the existence of text.txt file
and if the file text.txt is not found
you will create the text.txt file

import os
print "== if the file doesn't exist, create one =="
if os.path.exists('text.txt'):
    print "File exists"
    print "Creating the text.txt-file"
    my_file = open("text.txt", 'w')
    my_file.write("I'm the first line of the file!" +"\n")
    my_file.write("I'm the second line."+"\n")
    my_file.write("Third line here, boss."+"\n")

my_file = open("text.txt","r")
print my_file.readline()
print my_file.readline()
print my_file.readline()

== discussions / opinions ==


Thank you, I was getting the same error. I guess if the file does not exist, the quickest way to solve the problem is to create it. :slight_smile:

I am assuming the "." in os.listdir refers to the current directory?