Read those docs


#1

https://discuss.codecademy.com/t/challenge-anagram-detector/83127/3

Must not be reading the docs well enough. I have never used sorted() on a string, which explains my structured approach, earlier. Oddly enough, I never thought of comparing lists, either. (shakes head)

>>> sorted("bhgjtidkwl")
['b', 'd', 'g', 'h', 'i', 'j', 'k', 'l', 't', 'w']
>>> sorted("bhgjtidkwl") == sorted("bhgjtidkwl")
True
>>>

An obvious improvement, given this tiny bit of wherewithal. Kudos!

    return 1 if a == b else 0

would round out this one. Simple variables used for brevity in example.


[Challenge] Anagram Detector