Questions


#1



https://www.codecademy.com/en/courses/python-beginner-en-4XuFm/2/4?curriculum_id=4f89dab3d788890003000096


the code runs smoothly, but i just have a question:
why do you not have to def the variable for turn and it will be assumed to be zero?

thanks!


from random import randint

board = []

for x in range(5):
    board.append(["O"] * 5)

def print_board(board):
    for row in board:
        print " ".join(row)

print "Let's play Battleship!"
print_board(board)

def random_row(board):
    return randint(0, len(board) - 1)

def random_col(board):
    return randint(0, len(board[0]) - 1)

ship_row = random_row(board)
ship_col = random_col(board)
print ship_row
print ship_col

# Everything from here on should go in your for loop!
# Be sure to indent four spaces!
for turn in range(4):
    guess_row = int(raw_input("Guess Row:"))
    guess_col = int(raw_input("Guess Col:"))
    
    if guess_row == ship_row and guess_col == ship_col:
        print "Congratulations! You sunk my battleship!"
        break
    else:
        if (guess_row < 0 or guess_row > 4) or (guess_col < 0 or guess_col > 4):
            print "Oops, that's not even in the ocean."
        elif (board[guess_row][guess_col] == "X"):
            print "You guessed that one already."
        else:
            print "You missed my battleship!"
            board[guess_row][guess_col] = "X"
            if turn == 3:
                print "Game Over"
    # Print (turn + 1) here!
    print "Turn", turn + 1
    print_board(board)


#2

you mean here:

for turn in range(4):

?

turn gets defined in the loop, range() will produce a list and assign the values in list to range in order


#3

Yep but how does it know that turn = 0 initially? because it is not defined as such anywhere


#4

range() produces a list, the first value of which is 0, which gets assigned to turn in the first run of the loop


#5

oh okay i got it thanks!


#6

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