# Question about lists and dictionaries in 5/9

#1

<Below this line, add a link to the EXACT exercise that you are stuck at.>

<In what way does your code behave incorrectly? Include ALL error messages.>
It behaves fine, just have a question.

<What do you expect to happen instead?>
When taking inputs for the average(numbers) function, why does it ignore “name” and not throw an error for a string?

``````

lloyd = {
"name": "Lloyd",
"homework": [90.0, 97.0, 75.0, 92.0],
"quizzes": [88.0, 40.0, 94.0],
"tests": [75.0, 90.0]
}
alice = {
"name": "Alice",
"homework": [100.0, 92.0, 98.0, 100.0],
"quizzes": [82.0, 83.0, 91.0],
"tests": [89.0, 97.0]
}
tyler = {
"name": "Tyler",
"homework": [0.0, 87.0, 75.0, 22.0],
"quizzes": [0.0, 75.0, 78.0],
"tests": [100.0, 100.0]
}

def average(numbers):
total = sum(numbers)
total = float(total)
total = total / len(numbers)
``````

#2

the only thing the `average` function is designed to do is calculating the average value of a list with numbers (float and/or integers)

functions only execute when called, you haven’t called the function yet. So its only getting interpreted by the python interpreted, it doesn’t actually execute

as such, the function parameter (`numbers`) is only a placeholder until it gets its value from argument at function call

lets clarify all this by adding a function call:

``````def average(numbers):
total = sum(numbers)
total = float(total)
total = total / len(numbers)

average(lloyd['homework'])
``````

here i calculated the average grade for lloyd his homework

so the function parameter (`numbers`) gets its value from the function argument (`lloyd['homework']`) at function call

if we where to pass the name into the function:

``````average(lloyd['name'])
``````

we would get an error

#3

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