I was just doing the ‘rock, paper, scissors’ exercise on the full stack course, and had a thought while inputing some parameters into an if statement. The answer to this particular exercise is to use the || or logical operator and to ask for one of three options. Could the same result be returned with either of the two codebytes below:
const getUserChoice = userInput => {
userInput - userInput.toLowerCase();
if(userInput === 'rock', 'paper', 'scissors'){
return userInput;
}
else{
console.log('Please select a valid option');
}
};
or
const getUserChoice = userInput => {
userInput - userInput.toLowerCase();
if(userInput === 'rock' || 'paper' || 'scissors'){
return userInput;
[codebyte]
[/codebyte]
}
else{
console.log('Please select a valid option');
}
};
rather than writing:
const getUserChoice = userInput => {
userInput - userInput.toLowerCase();
if(userInput === 'rock' || userInput === 'paper' || userInput === 'scissors'){
return userInput;
}
else{
console.log('Please select a valid option');
}
};
Just thought there may be a short hand way to write this same code. Any help would be much appreciated.