Python Student Becomes Teacher 5/9


#1

Please what's wrong with this code?

lloyd = {
    "name": "Lloyd",
    "homework": [90.0, 97.0, 75.0, 92.0],
    "quizzes": [88.0, 40.0, 94.0],
    "tests": [75.0, 90.0]
}
alice = {
    "name": "Alice",
    "homework": [100.0, 92.0, 98.0, 100.0],
    "quizzes": [82.0, 83.0, 91.0],
    "tests": [89.0, 97.0]
}
tyler = {
    "name": "Tyler",
    "homework": [0.0, 87.0, 75.0, 22.0],
    "quizzes": [0.0, 75.0, 78.0],
    "tests": [100.0, 100.0]
}

# Add your function below!
   def average(numbers):
     total = sum(numbers)
     total = float(total)/len(numbers)
   return total

#2

Make sure that the function average is indented properly. It looks like it might not be correctly indented.


#3

def average(numbers):
total = sum(numbers)
total = float(total)
average = total / len(numbers)
return average

You need to return the average, not the total.
set the float(total) / len(numbers) equal to the average.


#4

How does the code know what the variable "numbers" is? is it because you can't add strings together?


#5

Hello

objectjumper57813

u may getting the syntax error it's
SyntaxError: 'return' outside function

to correct it by writing return function inside the average function . Look below the code

def average(numbers):
total = sum(numbers)
n = len(numbers)
total = float(total)/n
return total


#6

It's not that, you can return total but you have to do it in the right place: inside the function


#7

You should return total in the right place: inside the function.
Like this:

def average(numbers):
    total=sum(numbers)
    total=float(total)/len(numbers)
    return total

Compare this snippet with your average function!


#8