I don't get the instructions!!

Question 1. it says: Set bool_one equal to the result of False and False. Set bool_five equal to the result of True and True

do I have to write "False and False" or 1 != 1.

Question 2. it says : Set bool_two equal to the result of -(-(-(-2))) == -2 and 4 >= 16**0.5

Set bool_three equal to the result of 19 % 4 != 300 / 10 / 10 and False

Set bool_four equal to the result of -(1**2) < 2**0 and 10 % 10 <= 20 - 10 * 2

do i have to figure out the equation?

# Python Boolean Operators No. 6. And

**nedwards**#2

Don't forget the following when thinking in terms of booleans:

```
True and True == True
True and False == False
False and True == False
False and False == False
True or True == True
True or False == True
False or True == True
False or False == False
Not True == False # !(True) == False
Not False == True # !(False) == True
```

With those in mind, the exercise in your first question is asking you to set `bool_one`

to the **result** of `False and False`

.

The same principle applies to your second question - you need to decide whether the statement `-(-(-(-2))) == -2 and 4 >= 16**0.5`

is `True`

or `False`

, and set the value of `bool_two`

accordingly.

They do look tricky at first sight, but if you do it one step at a time:

```
-2 == -2 # True
-(-2) == -2 # False, because -(-2) is the same as 2
-(-(-2)) == -2 # True, because -(-(-2)) is the same as -2
-(-(-(-2))) == -2 # False, because -(-(-(-2))) is the same as 2
```

`4 >= 16**0.5 # True, because 16**0.5 is 4`

Taking the two statements together you have a case where one is `False`

and the other is `True`

. In other words, `bool_two`

should be set to the result of **True and False** (look in the table I provided above).

You will have to do the same for `bool_three`

and onwards - if you have trouble with the symbols, here's a handy overview of them.

**randy3465**#4

I am having problem with bool_four:

Is this not the correct answer?:

bool_four = -1<1 and 0<=0 is True

Thank you.

**system**#5

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