# Product

#1

Oops, try again. Your function crashed on [4, 5, 5] as input because your function throws a "list index out of range" error.

the result is correct but sthg wrong

``````def product(l):
p = 1
for a in range(l[0],l[len(l)-1]):
p *= l[a]
return p
print product([1,2,3,4,5])
b = 1*2*3*4*5
print b``````

#2

here:

``l[len(l)-1]``

i get length minus one to calculate till where the loop should loop, but no need to retrieve the value from list using square brackets

#3

sorry but I don't understand what u want say?

#4

why `l[]`? length minus one is a perfect stop value for range

#5

You don't need index looping here.
You just can loop over it.

We learnt two types of looping ...

Don't use index looping over a sequence

``````tab = [1,2,3,4]

for i in range(len(tab)) :
print tab[i]``````

rather use this one..

``````for j in tab :
print j``````

You'll get rid of many complexities of code that you have now!
I hope it helps you!

#6

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