problem1


#1

/*var userChoice = prompt("Do you choose rock, paper or scissors?");
var computerChoice = Math.random();
if (computerChoice < 0.34) {
computerChoice = "rock";
} else if(computerChoice <= 0.67) {
computerChoice = "paper";
} else {
computerChoice = "scissors";
} console.log("Computer: " + computerChoice);*/
var compare = function(choice1, choice2){
if (choice1 === choice2) {
return "The result is a tie!"

}
else if(choice1 === "rock") {
if(choice2 === "scissors") {
return "rock wins";

} else {
return "paper wins";
}
}
else if (choice1 === "paper"){
if(choice2 === "rock") {
return "paper wins"
} else {
return "scissors wins";
}
}
}

else if(choice1 === "scissors") {
if(choice2 === "rock") {
return "rock wins";
}
else {
return "scissors wins";
}
}
}
The third option has mistake.What is it? It s a syntax error.


#2

@stelios200,

The problem is the ending-of-the-second option.....
There you are using 3 closing-curly-bracket's-}
instead of the needed 2 .....
and therefor you have closed the =compare= function....


#3

How does it close? I m confused.


#4

@stelios200,

Please read
http://www.codecademy.com/forum_questions/559dcb4be39efe550f00006b
and concentrate on:

  • the creation of the compare function
  • the truth-table
  • the build of the IF ELSE-IF statement structure as part of the compare FUNCTION-BODY
  • the execution of the compare function (keeping in mind that the return statement is used )