# Print all three students average points without creating three “print”-strings?

#1

How do I print all three studens average points without creating three “print”-strings?

E.g.

``````print get_average(lloyd)
print get_average(alice)
print get_average(tyler)
``````
``````lloyd = {
"name": "Lloyd",
"homework": [90.0, 97.0, 75.0, 92.0],
"quizzes": [88.0, 40.0, 94.0],
"tests": [75.0, 90.0]
}
alice = {
"name": "Alice",
"homework": [100.0, 92.0, 98.0, 100.0],
"quizzes": [82.0, 83.0, 91.0],
"tests": [89.0, 97.0]
}
tyler = {
"name": "Tyler",
"homework": [0.0, 87.0, 75.0, 22.0],
"quizzes": [0.0, 75.0, 78.0],
"tests": [100.0, 100.0]
}

def average(numbers):
total = sum(numbers)
total = float(total)
total = total / len(numbers)

def get_average(student):
homework = average(student["homework"])
quizzes = average(student["quizzes"])
tests = average(student["tests"])
return 0.10 * average(student["homework"]) + 0.30 * average(student["quizzes"]) + 0.60 * average(student["tests"])
``````

#2

Have you considered looping over students list?

#3

Yeah I have. But I can’t figure out how to do that

Can you give me a few hints?

#4
``````students = [lloyd, alice, tyler]
``````

Note that the list contains object identifiers, not strings. It is a convenient way to access all three dictionaries in one place.

The dictionaries are not stored in the list, only their references.

Hint

``````for student in students:
# code here
``````

#5

I got it

``````students = [alice, tyler, lloyd]
for student in students:
print  + str(get_average(student))
print
``````

Another question - I would like to have their name before the avarage point for each student.

I was thinking if I could create a new dictionaries but also thought that it should be possible to get the names by using the existing dictionaries?

Can you give me a hint again

#6
``````for student in students:
print ("%s: %.2f" % (student['name'], get_average(student))``````

#7

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