# Practice Makes Perfect || Help please

#1

"Oops,try again. by_three(1) returned 1 instead of False"
and
"None" in the console window

I'm not putting in a by_three(1)

``````def cube(number):
return number**3
def by_three(number):
if number % 3:
return cube(number)
else:
return False``````

#2

That is the way that codecademy checks sometimes. It will plug numbers into your function and check the output to see if it's right. Let me ask you this though: `if number % 3 == ...?`

#3

Still didn't work when I put that in

#4

Don't type that exactly. I'm asking what would number % 3 be equal to if it was evenly divisible by 3? Any number divided by three with 0 left over.

#5

Not following you here. I'm piggybacking on the thread to get a hint too

#6

If we want to see if a number is evenly divisible by another number, when we divide, there will be no remainder. Since % returns the remainder from division, if we check to see if the answer is 0, then we can evenly divide it.

Example:

``````if 30 % 2 == 0:
return "The number is divisible by 2 evenly. It is therefore an even number."``````

#7

Got it to work.
Ended up putting in:
def cube(n):
return n**3
def by_three(n):
if n % 3 == 0:
return cube(n)
else:
return False

#8

def cube(number):
result=number**3

``  return result``

def by_three(number):
if number%3==0:
return cube(number)

else:
return False

#9

Hello

Return result needs to be under result=number**3.

I hope that helped. Try to remember that python uses indentations to put code into blocks.

#10

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