Part of the whole


#1



 lloyd = {
    "name": "Lloyd",
    "homework": [90.0, 97.0, 75.0, 92.0],
    "quizzes": [88.0, 40.0, 94.0],
    "tests": [75.0, 90.0]
}
alice = {
    "name": "Alice",
    "homework": [100.0, 92.0, 98.0, 100.0],
    "quizzes": [82.0, 83.0, 91.0],
    "tests": [89.0, 97.0]
}
tyler = {
    "name": "Tyler",
    "homework": [0.0, 87.0, 75.0, 22.0],
    "quizzes": [0.0, 75.0, 78.0],
    "tests": [100.0, 100.0]
}

# Add your function below!
def average(numbers):
    total = float(sum(numbers))
    x = ((total) / (len(numbers)))
    return x
    
def get_average(student):
    homework = average(student['homework'])
    quizzes = average(student['quizzes'])
    tests = average(student['tests'])
    return (homework*0.1)+(quizzes*0.3)+(tests*0.6)
    
def get_letter_grade(score):
    score = float(score)
    if score >= 90:
        return "A"
    elif score >= 80:
        return "B"
    elif score >= 70:
        return "C"
    elif score >= 60:
        return "D"
    else:
        return "F"

print get_letter_grade(get_average(lloyd))
print get_letter_grade(get_average(alice))
print get_letter_grade(get_average(tyler))

def get_class_average(students):
    students = [lloyd, alice, tyler]
    results = []
    for student in students:
        get_average(student)
        return results.append(get_average(students))
    return average(results)

I get get_class_average(alice)] resulted in an error: list indices must be integers, not str.

so I tried making students = [lloyd, alice, tyler] into float() but didn't work, how i'm I supposed to this?

why doesn't it gives an error for lloyd but does for alice?


#2

The reason you're getting an error message is because you are tring to return twice. How you should use the return keyword should be like this.

for student in students:
        results.append(get_average(student))
return average(results)

Whereas the line after the for loop only appends all the items into the empty list.. results.append(get_average(student))
Then the line after returns the average of the results.. (return average(results) ..that is after the for loop has gone through all the data. for student in students:


#3

aah thank you so much! thought that what "call" meant in the instructions got confused


#4

No problem mahn! please click the solution button below my answer! :slight_smile: