hi there, i was going mad at this exercise for just an indented error. The missplaced "return" gave me a wrong avg number > Oops, try again. get_class_average([alice, lloyd]) returned 91.15 instead of 85.85 as expected

after a while i realized that THIS:

def get_class_average(students):

results=[]

for student in students:

results.append(get_average(student))

*____ _return average(results)*

was different than THIS

def get_class_average(students):

results=[]

for student in students:

results.append(get_average(student))

*return average(results)*

can someone pls explain to me why a TAB changed the value of the whole code?!?

Thankssssss

```
lloyd = {
"name": "Lloyd",
"homework": [90.0, 97.0, 75.0, 92.0],
"quizzes": [88.0, 40.0, 94.0],
"tests": [75.0, 90.0]
}
alice = {
"name": "Alice",
"homework": [100.0, 92.0, 98.0, 100.0],
"quizzes": [82.0, 83.0, 91.0],
"tests": [89.0, 97.0]
}
tyler = {
"name": "Tyler",
"homework": [0.0, 87.0, 75.0, 22.0],
"quizzes": [0.0, 75.0, 78.0],
"tests": [100.0, 100.0]
}
# Add your function below!
def average(numbers):
total = sum(numbers)
return float(total) / len(numbers)
def get_average(student):
homework= average(student['homework'])
quizzes= average(student['quizzes'])
tests= average(student['tests'])
total = 0.1 * average(student['homework']) + 0.3 * average (student['quizzes']) + 0.6 * average(student['tests'])
return total
def get_letter_grade(score):
if score >= 90:
return "A"
elif score >= 80:
return "B"
elif score >= 70:
return "C"
elif score >= 60:
return "D"
else:
return "F"
print get_letter_grade(get_average(lloyd))
def get_class_average(students):
results=[]
for student in students:
results.append(get_average(student))
return average(results)
```