# Part of The Whole list integers?

#1

When I run the code I receive this message: 'Oops, try again. get_class_average([alice]) resulted in an error: list indices must be integers, not str'

Since I got no such formatting error in the previous parts of the problem, I don't understand why it's causing trouble. I've been stuck on this one for days.

``````lloyd = {
"name": "Lloyd",
"homework": [90.0, 97.0, 75.0, 92.0],
"quizzes": [88.0, 40.0, 94.0],
"tests": [75.0, 90.0]
}
alice = {
"name": "Alice",
"homework": [100.0, 92.0, 98.0, 100.0],
"quizzes": [82.0, 83.0, 91.0],
"tests": [89.0, 97.0]
}
tyler = {
"name": "Tyler",
"homework": [0.0, 87.0, 75.0, 22.0],
"quizzes": [0.0, 75.0, 78.0],
"tests": [100.0, 100.0]
}

def average(numbers):
total = sum(numbers)
total = float(total)
average = float(total)/len(numbers)
return average

def get_average(student):
homework = average(student["homework"])
quizzes = average(student["quizzes"])
tests = average(student["tests"])
return 0.1 * homework + 0.3 * quizzes + 0.6 * tests

if score >= 90:
return "A"
elif score >= 80:
return "B"
elif score >= 70:
return "C"
elif score >= 60:
return "D"
else:
return "F"

def get_class_average(students):
results = []
for student in students:
results.append(get_average(students))
return average(results)``````

#2

You are passing the entire `students` `list` as an argument here ...

``    results.append(get_average(students))``

#3

Ok I'll try with just one student?

#4

Thanks mate, problem solved

#5

Yes, within the loop, pass one `student` at a time. Each iteration of the loop will process an individual `student`.

#6