# Part of the Whole...FRUSTRATED!

#1

Part of the Whole

Oops, try again. get_class_average([alice, lloyd]) returned 91.15 instead of 85.85 as expected

Not sure why I don't see tyler, but guess it would work if I did right?

``````lloyd = {
"name": "Lloyd",
"homework": [90.0, 97.0, 75.0, 92.0],
"quizzes": [88.0, 40.0, 94.0],
"tests": [75.0, 90.0]
}
alice = {
"name": "Alice",
"homework": [100.0, 92.0, 98.0, 100.0],
"quizzes": [82.0, 83.0, 91.0],
"tests": [89.0, 97.0]
}
tyler = {
"name": "Tyler",
"homework": [0.0, 87.0, 75.0, 22.0],
"quizzes": [0.0, 75.0, 78.0],
"tests": [100.0, 100.0]
}

def average(numbers):
total = sum(numbers)
total = float(total)
divide = total / len(numbers)
return divide

def get_average(student):
homework = average(student["homework"])
quizzes = average(student["quizzes"])
tests = average(student["tests"])
return 0.10 * average(student["homework"]) + \
0.30 * average(student["quizzes"]) + \
0.60 * average(student["tests"])

if score >= 90:
return "A"
elif score >= 80 and score < 90:
return "B"
elif score >= 70 and score < 80:
return "C"
elif score >= 60 and score < 70:
return "D"
else:
return "F"

def get_class_average(students):
for student in students:
results = []
results.append(get_average(student))
return average(results)``````

#2

a function ends the moment a return keyword is reached, if the return keyword is reached in a loop, the loop breaks

Place return outside the loop so the whole loop can run

#3

Thanks for the response. I can go to left any further without an error saying return not in function. Also new error i receive is "Oops, try again. get_class_average([alice, lloyd]) returned 80.55 instead of 85.85 as expected"

``````def get_class_average(students):
for student in students:
results = []
results.append(get_average(student))
return average(results)``````

#4

results should be declared outside the loop, otherwise the list becomes empty each iteration of the loop, while it should persist the data append to it

#5

That did the trick! That was pretty tough for me!

#6