My solution for 3/33


#1
for(var i = 1; i <= 20; i++){
    
    if(((i % 3)==0) && ((i % 5)>0)){
        console.log("Fizz");
    }
    else if(((i % 5)==0) && ((i % 3)>0)){
        console.log("Buzz");
    }
    else if(((i % 3)==0) && ((i % 5) == 0)){
        console.log("FizzBuzz");   
    }
    else {
       console.log(i); 
    };
};

There may be simpler.


#2

Yes you can type this code :


#3

for (i=1; i < 21; i++){
if (i % 3 === 0){
if (i % 5 === 0){
console.log("FizzBuzz");
}
else{
console.log("Fizz");
};
}
else if (i % 5 === 0){
console.log("Buzz");
}
else{
console.log(i);
}
};


#4

Mine is close to coursesurfer02394 one