My Python Tic Tac Toe

My first project on python. Took me a really long time to understand the win logic and changing of the users part. Internet is a great tool for help. I was just wondering if I could make this code any cleaner or simpler open to new ideas on approaching this. Thanks

#Tic-tac-toe Board """ [ [-, -, -], [-, -, -], [-, -, -] ] user_input between 1-9 according to index above. if input isn't in the index ask user to go again check if user_input is already used, if so go again add input to board check for win: rows, columns, and diagonals switch between user inputs X-O will be inputs. """ board = [ ["-", "-", "-"], ["-", "-", "-"], ["-", "-", "-"] ] user = True # when true it refers to x, otherwise o turns = 0 def print_board(board): #this is printing the board in terminal for row in board: for slot in row: print(f"{slot} ", end="") # this is putting them all in a line print() #this is seperating each row, indent with slots. def quit(user_input): if user_input.lower() == "q": print("Thanks for playing") return True else: return False def check_input(user_input): if not isnum(user_input): return False # check if its a number user_input = int(user_input) if not bounds(user_input): return False # check if its 1 - 9 return True def isnum(user_input): if not user_input.isnumeric(): #determining ig input is a number. print("This is not a valid input, must be a number.") return False else: return True def bounds(user_input): if user_input > 9 or user_input < 1: #making sure the number is betweeen 1-9 print("This is number is out of bounds") return False else: return True def istaken(coords, board): row = coords[0] col = coords[1] if board[row][col] != "-": print("Position is already taken.") return True else: return False def coordinates(user_input): row = int(user_input / 3) col = user_input if col > 2: col = int(col % 3) return (row, col) def add_to_board(coords, board, active_user): row = coords[0] col = coords[1] board[row][col] = active_user def current_user(user): if user: return "x" else: return "o" def iswin(user, board): if check_row(user, board): return True #checks index for user having inputs in row for win. if check_col(user, board): return True #checks index for user having inputs in column for win. if check_diag(user, board): return True #checks index for user having inputs in a diagonal for win. return False def check_row(user, board): for row in board: complete_row = True for slot in row: if slot != user: complete_row = False break if complete_row: return True return False def check_col(user, board): for col in range(3): complete_col = True for row in range(3): if board[row][col] != user: complete_col = False break if complete_col: return True return False def check_diag(user, board): #top left to bottom right if board[0][0] == user and board[1][1] == user and board[2][2] == user: return True elif board[0][2] == user and board[1][1] == user and board[2][0] == user: return True else: return False while turns < 9: active_user = current_user(user) print_board(board) user_input = input("Enter a position between 1-9. Enter \"q\" to quit:") if quit(user_input): break if not check_input(user_input): print("Please try again.") continue user_input = int(user_input) - 1 coords = coordinates(user_input) if istaken(coords, board): print("Please try again.") continue add_to_board(coords, board, active_user) if iswin(active_user, board): print(f"{active_user.upper()} won!") break turns += 1 if turns == 9: print("Tie!") user = not user

Hello!

1. Show the user (`X` or `O`) in each position request like "Current player is: ".
2. Print the board when winning so the user can see the winning combination.

About code. You can use flat array for field and use slices (Built-in Functions ā Python 3.10.2 documentation) with `map` (Built-in Functions ā Python 3.10.2 documentation and 5. Data Structures ā Python 3.10.2 documentation) and `all` (Built-in Functions ā Python 3.10.2 documentation) to check winning combination. For example, to check one of diagonal you can use code such as `all([f == user for f in board[::4]])`.
This is only another solution, Iām not sure that it cleaner or better.

Good work!

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