My code isn't throwing error but I would like someone to explain something


#1

lloyd = {
"name": "Lloyd",
"homework": [90.0, 97.0, 75.0, 92.0],
"quizzes": [88.0, 40.0, 94.0],
"tests": [75.0, 90.0]
}
alice = {
"name": "Alice",
"homework": [100.0, 92.0, 98.0, 100.0],
"quizzes": [82.0, 83.0, 91.0],
"tests": [89.0, 97.0]
}
tyler = {
"name": "Tyler",
"homework": [0.0, 87.0, 75.0, 22.0],
"quizzes": [0.0, 75.0, 78.0],
"tests": [100.0, 100.0]
}

Add your function below!

def average(numbers):
total = float(sum(numbers)) / len(numbers)
return total

def get_average(student):
homework = average(student["homework"])
quizzes = average(student["quizzes"])
tests = average(student["tests"])

homework = 0.1 * homework
quizzes = 0.3 * quizzes
tests = 0.6 * tests 
return homework + quizzes + tests

def get_letter_grade(score):
if score >= 90:
return "A"
elif score >= 80:
return "B"
elif score >= 70:
return "C"
elif score >= 60:
return "D"
else:
return "F"

I've done some programming in C and Java but I'm new to Python and something about this code bugs me. I understand how to get it to work but I'd like to know why in my final function(get_letter_grade) it knows what the variable "score" is without me having to actually call upon the previous function and and assign it's return value in the new equation. Is it just a hierarchical thing with Python? as in it will just automatically run the return result of the previous function?
I just dislike it when code works and I don't know why as much as when it doesn't.


#2

@daine.bigham,

Add an extra code-line at the end-of-your-coding

 print "== End-of-my-Code =="

Everything displayed after this printout
will be the course-checker doing its work and sometimes giving an output....