Medical Ins. Costs, List and sorting question

[nikamura]

BUILD A RECOMMENDER SYSTEM

Working with Python Lists: Medical Insurance Costs Project

Sorting Lists
I need to sort a 2d list that have to different data: Name and cost of insurance
when i write 'medical_records.sort() it sorted by name but i need to sorted by cost insurance which is the second data
example [ (‘Moony’, 3500), (‘Runa’, 5000)]

[lisalisaj]

A few things here…

• please remember to include a link to the lesson to which your question is regarding.
• If you could please post your formatted code. Select the </> button or refer to this post here.

Did you use .zip() to combine the two lists? You can always re-arrange the order of the two lists in the .zip()

Perhaps these posts will help you? (this question comes up often and is available via )

Sorting 2D list with mixed types - Working with Python Lists: Medical Insurance Project

The exercise has you zip() two lists to a 2D list with the insurance cost the first element, the person’s name the second in each list. The 2D list, medical_records, looks like this: [(13262.0, ‘Mohamed’), (4816.0, ‘Sara’), (6839.0, ‘Xia’), (5054.0, ‘Paul’), (14724.0, ‘Valentina’), (5360.0, ‘Jide’), (7640.0, ‘Aaron’), (6072.0, ‘Emily’), (2750.0, ‘Nikita’), (12064.0, ‘Paul’), (‘8320.0’, ‘Priscilla’)] The exercise is to sort the 2D list by the float (insurance cost). I got the same answer as the…

Or,

Help with using sorted in python pls

Hi, I have a similar issue… I understand that I have to use a key in the sort() function and so I am able to sort the list by the insurance cost. However, the exercise shows that insurance cost should now come before name - since I zipped the original two lists with the name first and insurance cost second, is there a way to reverse the order within each nested list with some funky code other than just me reversing the order in the original zip()? If so, what terminology should I be Googling? …

There is also the Python docs to consider:

Sorting HOW TO

So…Considering all of this. You could sort it by using a lambda function and index. (Edit: I’m not sure if you’ve covered lambda functions yet).

Ex Hint:

Summary

names = ["Mohamed", "Sara", "Xia", "Paul", "Valentina", "Jide", "Aaron", "Emily", "Nikita", "Paul"]
insurance_costs = [13262.0, 4816.0, 6839.0, 5054.0, 14724.0, 5360.0, 7640.0, 6072.0, 2750.0, 12064.0]

medical_records = list(zip(insurance_costs, names))
print(medical_records)

medical_records.sort(key= lambda x: x[0])
print(medical_records)

>>> [(13262.0, 'Mohamed'), (4816.0, 'Sara'), (6839.0, 'Xia'), (5054.0, 'Paul'), (14724.0, 'Valentina'), (5360.0, 'Jide'), (7640.0, 'Aaron'), (6072.0, 'Emily'), (2750.0, 'Nikita'), (12064.0, 'Paul')]

>>>[(2750.0, 'Nikita'), (4816.0, 'Sara'), (5054.0, 'Paul'), (5360.0, 'Jide'), (6072.0, 'Emily'), (6839.0, 'Xia'), (7640.0, 'Aaron'), (12064.0, 'Paul'), (13262.0, 'Mohamed'), (14724.0, 'Valentina')]

[nikamura]

thank you very much for the answer. The problem was that it show me i needed to put the insurance costs first and then the name but i will chech the sorting HOW TO to learn how to modifie the list in-place.
Next time i will remember to put the link

[lisalisaj]

Sure thing.
Key takeaways:
.sort() sorts the list in place. .sorted() is a built in function and it works with any iterable and produces a new list. Both have a key parameter, ‘to specify a function (or other callable) to be called on each list element prior to making comparisons.’ (docs).