# Lists + Functions

#1

Lists + Functions

It doesn't return the fizz number but it says that I passed

``````Replace this line with your code.

def fizz_count (x):
count = 0
for item in x:
if item == "fizz":
count = count + 1
x= ["fizz", "dog", "fizz", "pie", "fizz"]
return count
print count``````

#2

Hi @mbeispel ,

Your function does compute and `return` the correct value, but your `print` statement follows the `return` and does not get executed.

Delete the `print` statement, and instead `print` the result of calling the function after the function definition.

This should also be outside the function definition ...

``x= ["fizz", "dog", "fizz", "pie", "fizz"]``

You can pass `x` as an argument when you call the function.

#3

I am confused what you mean by calling the function after the function
definition and passing x as the argument when you cal the function.

#4

Remove this statement from the function ...

``x= ["fizz", "dog", "fizz", "pie", "fizz"]``

Place it outside the function. It should not be indented, otherwise it will be part of the function.

Also remove this `print` statement from the function, as it follows the `return` statement, and can never execute ...

``print count``

Then, at the end of your code, the following statement can call the function and display the result ...

``print fizz_count(x)``

Be sure not to indent that final statement, otherwise it will be part of the function definition.

#5

i have made the corrections but it is still failing, I don't understand what the issue is:

def fizz_count (x):
count = 0
for item in x:
if item == "fizz":
count = count + 1

x=["fizz", "dog", "fizz", "pie", "fizz"]
print fizz_count(x)

#6

You lost the `return` statement, so now the function `return`s `None`.

#7

Got it. Thanks so much!

#8