# Letter input?

#1

Test Run - Battleship!!!

How do you make it so the computer prints a message like "Oops" when the user inputs a letter?

``````from random import randint

board = []

for x in range(0, 5):
board.append(["O"] * 5)

def print_board(board):
for row in board:
print " ".join(row)

print_board(board)

def random_row(board):
return randint(0, len(board) - 1)

def random_col(board):
return randint(0, len(board[0]) - 1)

ship_row = random_row(board)
ship_col = random_col(board)
guess_row = int(raw_input("Guess Row:"))
guess_col = int(raw_input("Guess Col:"))

print ship_row
print ship_col

if guess_row == ship_row and guess_col == ship_col:
print "Congratulations! You sank my battleship!"
if guess_row not in range(5) or guess_col not in range(5):
print "Oops, that's not even in the ocean."
elif board[guess_row][guess_col] == 'X':
print 'You guessed that one already.'
else:
print "You missed my battleship!"
board[guess_row][guess_col] = 'X'
print print_board(board)``````

#2

you can import the string module and check if the inputted values are equal to a letter.

or even simpler,

``````get_in = raw_input("Number: ")

if type(get_in) != int:
print("I only like numbers.")``````

#3

to enhance @dave.n solution:

``````while True:
get_in = raw_input("Number: ")

if type(get_in) != int:
print("I only like numbers.")
else:
break``````

this will keep prompting the user until the user enters something valid. Or:

``````while True:
try:
guess_row = int(raw_input("Guess Row:"))
guess_col = int(raw_input("Guess Col:"))
except ValueError:
print "that is not valid, try again"
else:
break``````

To Your Battle Stations! - Bit of a curiosity
#4

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