# Kelvin Weather (step 11 )

I am currently trying to finish the kelvin weather objective. in step 11 it instructs us to go back to the const kelvin var. and change it to 0 which should change the Fahrenheit to -460 however I change the const to 0 , however it doesn’t change to -460 in Fahrenheit. i looked through my code checking it but I don’t see anything wrong with it. I also checked with the video, can anyone see any error in my code that I’m not seeing by any chance?

//kelvin is constant and will be turned to c and then f

const kelvin = 0;

//i shouldn’t have to change 20c so there is no reason to use let

const celsius = 20;

//whatever number that is given from this equation it will be set as the number for fahrenheit

let fahrenheit = celsius * (9 / 5) + 32;

//to make sure that fahrenheit is not a decimail by using the math .floor() method it rounds the result down to the nearist whole number

fahrenheit = Math.floor(fahrenheit);

console.log(`The temperature is \${fahrenheit} degrees Fahrenheit`);

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Apart from the declaration and initialization of `kelvin`, you are not using this variable anywhere else in your pasted code. So, changing the value assigned to this variable is not having any effect.

Have a look at Step 3 again (look at the hint for the step as well). You have simply subtracted `273` from `293` and assigned `20` to `celsius`. You want this calculation to be done not by you, but by your code using an expression involving the `kelvin` variable.