# Just weight and see

#1

In the description it's written to take "student" in parentheses but i didn't define a variable "student" earlier but still output is correct with "student". Who so?
Output is also correct if I replace student with lloyd or alice or tyler. But this I understand because I've defined these 3 names but not "student". So why the output is correct?

#4

### the FUNCTION talk

``````def myFunc( param1, param2):
# Begin of =myFunc= FUNCTION-BODY
# this =myFunc= function- has 2 PARAMETERS param1 and param2
# param1 and param2 PARAMETERS are used
# as -local- VARIABLES throughout the =myFunc= FUNCTION-BODY
print( param1 + " and " + param2 )
#End of =myFunc= FUNCTION-BODY``````

If you want to call/execute the myFunc function
you will have to add a pair of parentheses to myFunc
like
myFunc()
As the myFunc function was defined
as having 2 parameters
you have to provide 2 arguments
in our case 2 string VALUES "Alena" and "Lauren"
like
myFunc("Alena","Lauren")

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
++++ function with 1 parameter using return-statement

``````def myFunction( param1 ):
# //Begin of =myFunction= FUNCTION-BODY
# //=myFunction= function has 1 PARAMETER param1
# //this param1 PARAMETER is used as a -local- VARIABLE
# //throughout the =myFunction= FUNCTION-BODY
return param1;
# //End of FUNCTION-BODY``````

You have defined a myFunction function
which takes 1 parameter param1
this param1 parameter is used
as a variable throughout the =myFunction= FUNCTION-BODY.

If you want to call/execute this myFunction function
and this myFunction function was defined
as having 1 parameter param1
you will have to provide 1 argument
in our case a "number VALUE" 4
myFunction( 4 )

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

#### ============================================

As you are using the return-statement in your myFunction function
you will only get a return-value no-display.
You can however capture this return-value in a variable
and then use the print-method to do a display.

``````theResult = myFunction( 4 )
print theResult``````

OR directly

``print myFunction( 4 )``

#5

lloyd = {
"name": "Lloyd",
"homework": [90.0, 97.0, 75.0, 92.0],
"quizzes": [88.0, 40.0, 94.0],
"tests": [75.0, 90.0]
}
alice = {
"name": "Alice",
"homework": [100.0, 92.0, 98.0, 100.0],
"quizzes": [82.0, 83.0, 91.0],
"tests": [89.0, 97.0]
}
tyler = {
"name": "Tyler",
"homework": [0.0, 87.0, 75.0, 22.0],
"quizzes": [0.0, 75.0, 78.0],
"tests": [100.0, 100.0]
}

student = ["lloyd","alice","tyler"]
def get_average(student):
homework = average(student["homework"])
quizzes = average(student["quizzes"])
tests = average(student["tests"])
return (homework*0.1)+(quizzes*0.3)+(tests*0.6)

def average(numbers):
total = sum(numbers)
print total
total = float(total)
total = total / len(numbers)

get_average(student)

it throws an error like "Traceback (most recent call last):
File "python", line 34, in
File "python", line 22, in get_average
TypeError: list indices must be integers, not str"

i m not sure whats wrong...help!!!

#6

### 1

You will have to change your student =list= with the 3 string elements
into
a student =list= with 3 variables which will evaluate to 3 =dictionaries=

``student = [lloyd,alice,tyler]``

###2 And call the get_average() function with 1 student as ARGUMENT like

``get_average(lloyd)``

#7

How would you do this without having to put each student as an argument as instructions tell us to use student['homework']. By doing with having a list thought it would work, but keeps saying its not an integer but a string

#8