Javascript-Kelvin Weather

enikardie · November 15, 2019, 1:01am

Need help with my first Javascript exercise. I followed the video instructions to do this project , but it won’t render the correct answer

gist.github.com

https://gist.github.com/codecademydev/f3ffbd103ce98540988eed797a5b60dd

app.js

//Current temperature in kelvin degrees
const kelvin = 0;
//converting kelvin to Celsius
const celsius = kelvin - 273;
//Convert celsius to Fahrenheit
let fahrenheit = celsius * (9/5) + 32;
//Rounding down fahrenheit
Fahrenheit = Math.floor(fahrenheit);
console.log('The temperature is ${fahrenheit} degrees fahrenheit.');
let Newton = celsius * (33/100);

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//Current temperature in kelvin degrees
const kelvin = 0;
//converting kelvin to Celsius
const celsius = kelvin - 273;
//Convert celsius to Fahrenheit
let fahrenheit = celsius * (9/5) + 32;
//Rounding down fahrenheit
Fahrenheit = Math.floor(fahrenheit);
console.log(‘The temperature is {fahrenheit} degrees fahrenheit.'); let Newton = celsius * (33/100); Newton = Math.floor(Newton); console.log('The temperature is {Newton} degrees Newton.’);

vic-st · March 14, 2020, 7:10pm

Hey @enikardie!

Remember that you must use backticks when you use the new ES6 string interpolation syntax.

Also, would you please send the link to the exercise?

paratablet9648384657 · November 15, 2019, 2:35pm

i think that you are using the wrong apostrophe… you are using (’) that is for text like quots(") and you should use (` ), but I dont remenber the name, “right accent?”… perhaps is one solution…

and i usually take a mistake with caps… I don’t remember this exercise, but be carefully with this. I spend a lot of time searching a mistake and not defined variables, and the answer is a capital letter…

vic-st · November 15, 2019, 2:35pm

Hey @paratablet9648384657.

It’s called a backtick, and yes, that is what his code is missing. It should work fine once he fixes this.

definitely true, you want to be careful with this, but in the situation he presented, there was no problem.

paratablet9648384657 · November 15, 2019, 2:38pm

sorry, sometimes I don’t translate correctly, and didn’t see that you answered

enikardie · November 16, 2019, 1:47am

@stevencopeland. Thank you for your help!! I made the changes and it worked. I wa using the apostrophe instead of the backtick.

@paratablet9648384657. Thank you!!

enikardie · November 16, 2019, 1:47am

gist.github.com

https://gist.github.com/codecademydev/021bcf243874258fb45b58c2b7078e56

app.js

//Current temperature in kelvin degrees.
const kelvin = 0;
//converting kelvin to Celsius.
const celsius = kelvin - 273;
//Convert celsius to Fahrenheit.
let fahrenheit = celsius * (9/5) + 32;
//Rounding down fahrenheit.
fahrenheit = Math.floor(fahrenheit);
console.log(`The temperature ${fahrenheit} degrees fahrenheit.`);
let Newton = celsius * (33/100);

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dev1852195855 · February 4, 2021, 10:37pm

Just managed to do this now with some of your help:

gist.github.com

https://gist.github.com/codecademydev/181246c192ede57483e1927af84600ce

app.js

let Kelvin = 1000;

Kelvin -= 273;

let celsius = Kelvin;

let fahrenheit = celsius*(9/5) + 32

fahrenheit = Math.floor(fahrenheit);

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dev1852195855 · February 4, 2021, 10:38pm

You should be able to play around with Kelvin and it should it convert it when you run the programme again.