JavaScript Code Help

let story = ‘Last weekend, I took literally the most beautiful bike ride of my life. The route is called “The 9W to Nyack” and it actually stretches all the way from Riverside Park in Manhattan to South Nyack, New Jersey. It’s really an adventure from beginning to end! It is a 48 mile loop and it basically took me an entire day. I stopped at Riverbank State Park to take some extremely artsy photos. It was a short stop, though, because I had a really long way left to go. After a quick photo op at the very popular Little Red Lighthouse, I began my trek across the George Washington Bridge into New Jersey. The GW is actually very long - 4,760 feet! I was already very tired by the time I got to the other side. An hour later, I reached Greenbrook Nature Sanctuary, an extremely beautiful park along the coast of the Hudson. Something that was very surprising to me was that near the end of the route you actually cross back into New York! At this point, you are very close to the end.’;

let overusedWords = [‘really’, ‘very’, ‘basically’];

let unnecessaryWords = [‘extremely’, ‘literally’, ‘actually’ ];

const storyWords = story.split(" ");

//console.log(storyWords);
//console.log(storyWords.length);

const betterWords = story.filter(word => {
if(word !== ‘extremely’ && word !== ‘literally’ && word !== ‘actually’){
return word;
}});

Why am I getting the following error?

Why is it not accepting .filter()?

Hey @bhb23955!
I notice that you split the string story in to the array storyWords but instead of using the storyWords array, you still use the original variable. I think that may be your problem.

2 Likes

As Steven said, the problem is with the object you are attempting to filter. story is a string object, which has no filter method. storyWords is an array, which does have a filter method.

Something to bear in mind when using filter, it should not need an if statement since the callback is a predicate function.

object.filter(x => ____ )

All the words you want to filter out are listed in a single array. We want the callback to return any words that are not in that list. Have you considered using includes and ! in your callback?

1 Like