JavaScript Challenge - Reverse Words

FAQ
#1

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This community-built FAQ covers the “Reverse Words” code challenge in JavaScript. You can find that challenge here, or pick any challenge you like from our list.

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#2

I’m using brilliant and a bit tricky (especially in technical interviews context :slight_smile: ) function reduceRight here.

function wordReverser(phrase) {
  const phraseArray = phrase.split(' ');
  const res = phraseArray.reduceRight((acc, curr) => ([...acc, curr]), []);
  return res.join(' ');
}

console.log(wordReverser("Codecademy rules"));

// Leave this so we can test your code:
module.exports = wordReverser;
#3

My go at it:

function wordReverser(phrase) {
** // Write your code here**
** return phrase.split(" “).reverse().join(” ");**
}

console.log(wordReverser(“Codecademy rules”));

// Leave this so we can test your code:
module.exports = wordReverser;

1 Like
#4

function wordReverser(phrase) {
// Write your code here
phrase = phrase.split(" “)
return phrase.reverse().join(” ");
}

console.log(wordReverser(“Codecademy rules”));

// Leave this so we can test your code:
module.exports = wordReverser;

2 Likes
#5

function wordReverser(phrase) {
const split = phrase.split(" “).reverse().join(” ");
return split;

}

console.log(wordReverser(“Codecademy rules”));

// Leave this so we can test your code:
module.exports = wordReverser;

1 Like
#6 
const wordReverser = (phrase) => phrase.split(" ").reverse().join(" ");

// Leave this so we can test your code:
console.log(wordReverser("May the Fourth be with you"))
module.exports = wordReverser;
#8 
function wordReverser(phrase) {
  const words = phrase.split(" ");
  const reversed = [];
  for (let i = words.length-1; i >= 0; i--){
    reversed.push(words[i])
  }
  return (reversed.join(" "))
}

console.log(wordReverser("Codecademy rules"));

// Leave this so we can test your code:
module.exports = wordReverser;

#9

My solution:

function wordReverser(phrase) {
  // Write your code here
  let words = phrase.split(" ")
  let reversedWord = words.reverse()

  return reversedWord.join(" ")
}

console.log(wordReverser("Codecademy rules"));

// Leave this so we can test your code:
module.exports = wordReverser;
#10

function wordReverser(phrase) {
const tempArr = ;
phrase.split(" ").reverse().map(x => tempArr.push(x));

return tempArr.join(" ")

}

console.log(wordReverser(“Codecademy rules”));

// Leave this so we can test your code:
module.exports = wordReverser;

#11 
function wordReverser(phrase) {
  return phrase.split(" ").reverse().join(" ");
}

console.log(wordReverser("Codecademy rules"));

// Leave this so we can test your code:
module.exports = wordReverser;
#12 
function wordReverser(phrase) {
  return phrase
  .split(' ') //Split the string on the space
  .reverse() //Reverse the split array
  .join(' ') //Join it back to a string
}

console.log(wordReverser("Codecademy rules"));

// Leave this so we can test your code:
module.exports = wordReverser;
#13

I think my solution is a bit long, I kinda went step by step solving using method I know, not trying to optimize.
Just wondering if this kind of approach is still okay, for work interview for example?
Thanks for feedback :slight_smile:

function wordReverser(phrase) {
let phraseArray = phrase.split(’ ');
let reverseArray = ;
let finalPhrase = ‘’;
for (let i=phraseArray.length -1; i>=0; i–) {
reverseArray.push(phraseArray[i]);
}
finalPhrase = reverseArray.toString();
return finalPhrase.replace(/,/g, ’ ');
}

console.log(wordReverser(“My name is the John Doe”));

// Leave this so we can test your code:
module.exports = wordReverser;

#14 
const wordReverser=_=>_.split(" ").reverse().join(" ")
// Leave this so we can test your code:
module.exports = wordReverser;
#15

const wordReverser = (phrase) => {
return phrase.split(’ ‘).reverse().join(’ ')
}

console.log(wordReverser(“Codecademy rules”));

// Leave this so we can test your code:
module.exports = wordReverser;