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Top Discussions on the JavaScript challenge Reverse Words
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I’m using brilliant and a bit tricky (especially in technical interviews context ) function reduceRight here.
function wordReverser(phrase) {
const phraseArray = phrase.split(' ');
const res = phraseArray.reduceRight((acc, curr) => ([...acc, curr]), []);
return res.join(' ');
}
console.log(wordReverser("Codecademy rules"));
// Leave this so we can test your code:
module.exports = wordReverser;
const wordReverser = (phrase) => phrase.split(" ").reverse().join(" ");
// Leave this so we can test your code:
console.log(wordReverser("May the Fourth be with you"))
module.exports = wordReverser;
function wordReverser(phrase) {
// Write your code here
let words = phrase.split(" ")
let reversedWord = words.reverse()
return reversedWord.join(" ")
}
console.log(wordReverser("Codecademy rules"));
// Leave this so we can test your code:
module.exports = wordReverser;
function wordReverser(phrase) {
return phrase.split(" ").reverse().join(" ");
}
console.log(wordReverser("Codecademy rules"));
// Leave this so we can test your code:
module.exports = wordReverser;
function wordReverser(phrase) {
return phrase
.split(' ') //Split the string on the space
.reverse() //Reverse the split array
.join(' ') //Join it back to a string
}
console.log(wordReverser("Codecademy rules"));
// Leave this so we can test your code:
module.exports = wordReverser;
I think my solution is a bit long, I kinda went step by step solving using method I know, not trying to optimize.
Just wondering if this kind of approach is still okay, for work interview for example?
Thanks for feedback
function wordReverser(phrase) {
let phraseArray = phrase.split(’ ');
let reverseArray = ;
let finalPhrase = ‘’;
for (let i=phraseArray.length -1; i>=0; i–) {
reverseArray.push(phraseArray[i]);
}
finalPhrase = reverseArray.toString();
return finalPhrase.replace(/,/g, ’ ');
}
console.log(wordReverser(“My name is the John Doe”));
// Leave this so we can test your code:
module.exports = wordReverser;