JavaScript Challenge - Reverse a Singly-Linked List

This community-built FAQ covers the “Reverse a Singly-Linked List” code challenge in JavaScript. You can find that challenge here, or pick any challenge you like from our list.

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Hello everyone, :smiley:

I resolved that challenge and want to share my answer with you :

function reverseLinkedList(linkedList) {
//linkedList argument represents the head of the Linked List

let prevPointer = null
let currentPointer = linkedList
let nextPointer = null

while (currentPointer !== null) {

//the pointer that should come after the current pointer now comes before the current pointer
prevPointer = currentPointer.next
//the first pointer will be the last so the next pointer of the current pointer should be null for the first iteration
currentPointer.next = nextPointer
//the pointer that will be the next pointer must be the current pointer
nextPointer = currentPointer
//the current pointer should now be the previous pointer of the initial current pointer
currentPointer = prevPointer

}
return nextPointer
}

Enjoy coding everyone ! :jigsaw: :wink: