Java Challenge - Calculate the Mean and Mode

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I calculated the frequency of each number in the array, and I used a loop in a loop to do that.
So this is O(n^2)
I stored all the frequencies in another array, which probably was not necessary.

public class StatsFinder {
  public static void main(String[] args) {
    int[] testArray = new int[]{500, 400, 400, 375, 300, 350, 325, 300};
    double[] ans = statsFinder(testArray);
    System.out.print(", ");

  public static double[] statsFinder(int[] array) {
    int length = array.length;
    if (length < 1) {
      return new double[]{0.0, 0.0};
    int sum = 0;
    int[] frequency = new int[length];
    int maxFrequency = 0;
    int valueWithMaxFrequency = array[0];
    for (int i = 0; i < length; i++) {
      sum += array[i];
      frequency[i] = 0;
      for (int j = 0; j < length; j++) {
        if (array[j] == array[i]) {
          frequency[i] ++;
      if (frequency[i] > maxFrequency) {
        valueWithMaxFrequency = array[i];
        maxFrequency = frequency[i];
    double mean = (double)sum / length;
    return new double[]{mean, valueWithMaxFrequency};

No curly braces:

public static double[] statsFinder(int[] array) {
    // Write your code here

    double mean = 0;
    double mode = 0;
    double[] returnValue = new double[2];
    int[] occ = new int[array.length];
    int max = 0;

    for(int e:array)

/*calculate occurrences*/
    for(int i = 0; i < array.length; ++i)
      for(int j = 0; j < i; ++j)
        if(array[i] == array[j])

/*filter the most occurring*/
    for(int i : occ)
  returnValue[0] = mean;
  returnValue[1] = mode;
  return returnValue;