It's Okey to be Average


#1



It's Okey to be Average


the error message is "Oops, try again. average([3, 0]) resulted in an error: list indices must be integers, not str"


what's wrong with my code?


lloyd = {
    "name": "Lloyd",
    "homework": [90.0, 97.0, 75.0, 92.0],
    "quizzes": [88.0, 40.0, 94.0],
    "tests": [75.0, 90.0]
}
alice = {
    "name": "Alice",
    "homework": [100.0, 92.0, 98.0, 100.0],
    "quizzes": [82.0, 83.0, 91.0],
    "tests": [89.0, 97.0]
}
tyler = {
    "name": "Tyler",
    "homework": [0.0, 87.0, 75.0, 22.0],
    "quizzes": [0.0, 75.0, 78.0],
    "tests": [100.0, 100.0]
}

# Add your function below!
def average(numbers):
    total = sum(numbers['homework']) + sum(numbers['quizzes']) + sum(numbers['tests'])
    total = float(total)
    av = total/(len(numbers['homework']) + len(numbers['quizzes']) + len(numbers['tests']))
    return av


#2

numbers, your function parameter just contains a list ([3,0] for example) of which you need to calculate the average:

def average(numbers):
     print numbers

average([3, 0])

see the function call? This is what your function should handle, a list with integers


#3

i'm think too much!! thank you!


#4

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