It's Okay to be Average


#1



https://www.codecademy.com/courses/python-beginner-en-qzsCL/1/1?curriculum_id=4f89dab3d788890003000096#

Oops, try again. average([3, 0]) resulted in an error: local variable 'total' referenced before assignment

I don't know how to do the task...

lloyd = {
    "name": "Lloyd",
    "homework": [90.0, 97.0, 75.0, 92.0],
    "quizzes": [88.0, 40.0, 94.0],
    "tests": [75.0, 90.0]
}
alice = {
    "name": "Alice",
    "homework": [100.0, 92.0, 98.0, 100.0],
    "quizzes": [82.0, 83.0, 91.0],
    "tests": [89.0, 97.0]
}
tyler = {
    "name": "Tyler",
    "homework": [0.0, 87.0, 75.0, 22.0],
    "quizzes": [0.0, 75.0, 78.0],
    "tests": [100.0, 100.0]
}

# Add your function below!
def average(numbers):
    total+=sum(numbers)
    average=float(total)/len(numbers)
    return average


#2

here:

total+=sum(numbers)

+= is a shorthand for total = total + sum(numbers), which means you use total before defining total

you can just store the sum of numbers in total (use a single equal sign without +)


#3

yes. I get! Thanks a lot!:grin:


#4