It looks like your function output -1 instead of 0


#1

I've done:
def greater_less_equal_5(answer):
if 2 > 5 :
return 1
elif 2 < 5 :
return -1
else:
return 0

print greater_less_equal_5(4)
print greater_less_equal_5(5)
print greater_less_equal_5(6)

except it still says: Oops, try again. It looks like your function output -1 instead of 0 when answer is 5. Make sure you filled in the if and elif statements correctly!


99 problems. nothing seems to work. iv shifted thro topics also
#2

@kouna,
Could you provide the Instructions ??


#3

Spoiler:

Instead "______" you should write:
in row 2: answer>5
in row 4: answer<5
btw: before reset the code below on the web page.


#4

@kouna
They ask you to use answer > 5
then why are you using 2>5 ???

They are trying to make it clear
that if you are defining a function giving it a parameter like answer
you use this parameter as a =local= variable
within the so-called function-body.

This answer variable will get its value
at the moment that you call the greater_less_equal\ _5() function
providing a so-called argument
like

greater_less_equal_5(4)

where you used a number Value 4.

the FUNCTION talk

def myFunc( param1, param2):
    # Begin of =myFunc= FUNCTION-BODY
    # this =myFunc= function- has 2 PARAMETERS param1 and param2
    # param1 and param2 PARAMETERS are used 
    # as -local- VARIABLES throughout the =myFunc= FUNCTION-BODY
    print( param1 + " and " + param2 )
    #End of =myFunc= FUNCTION-BODY

If you want to call/execute the myFunc function
you will have to add a pair of parentheses to myFunc
like
myFunc()
As the myFunc function was defined
as having 2 parameters
you have to provide 2 arguments
in our case 2 string VALUES "Alena" and "Lauren"
like
myFunc("Alena","Lauren")

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
++++ function with 1 parameter using return-statement

def myFunction( param1 ):
    # //Begin of =myFunction= FUNCTION-BODY
    # //=myFunction= function has 1 PARAMETER param1
    # //this param1 PARAMETER is used as a -local- VARIABLE
    # //throughout the =myFunction= FUNCTION-BODY
    return param1;
    # //End of FUNCTION-BODY

You have defined a myFunction function
which takes 1 parameter param1
this param1 parameter is used
as a variable throughout the =myFunction= FUNCTION-BODY.

If you want to call/execute this myFunction function
and this myFunction function was defined
as having 1 parameter param1
you will have to provide 1 argument
in our case a "number VALUE" 4
myFunction( 4 )

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

============================================

As you are using the return-statement in your myFunction function
you will only get a return-value no-display.
You can however capture this return-value in a variable
and then use the print-method to do a display.

theResult = myFunction( 4 )
print theResult

OR directly

print myFunction( 4 )

#5

i figured it out already to use the word answer not a number.