def cube(number):

return number ** number

def by_three(number):

if number % 3 == 0:

return by_three(cube(number))

else:

return False

The instructions:

First, `def`

a function called `cube`

that takes an argument called `number`

. Don’t forget the parentheses and the colon!

Make that function `return`

the cube of that number ( *i.e.* that number multiplied by itself and multiplied by itself once again).

Define a second function called `by_three`

that takes an argument called `number`

.

`if`

that number is divisible by 3, `by_three`

should call `cube(number)`

and `return`

its result. Otherwise, `by_three`

should `return False`

.

Don’t forget that `if`

and `else`

statements need a `:`

at the end of that line!