Is there something wrong?


#1

I have the same problem here, and the error thingamabob shows the same message. Here's my code:

def shut_down(s):
if "yes":
return "Shutting down"
elif "no":
return "Shutdown aborted"
else:
return "Sorry"

Is there something wrong? It would be really great if someone could clear things up for me.

:slight_smile:


17. Review: Functions
#2

@epiccoolness,

the FUNCTION talk

def myFunc( param1, param2)
    # Begin of =myFunc= FUNCTION-BODY
    # this =myFunc= function- has 2 PARAMETERS param1 and param2
    # param1 and param2 PARAMETERS are used 
    # as -local- VARIABLES throughout the =myFunc= FUNCTION-BODY
    print( param1 + " and " + param2 )
    #End of =myFunc= FUNCTION-BODY
end

If you want to call/execute the myFunc function
you will have to add a pair of parentheses to myFunc
like
myFunc()
As the myFunc function was defined
as having 2 parameters
you have to provide 2 arguments
in our case 2 string VALUES "Alena" and "Lauren"
like

myFunc("Alena","Lauren")

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
++++ function with 1 parameter using return-statement

def myFunction( param1 )
    # //Begin of =myFunction= FUNCTION-BODY
    # //=myFunction= function has 1 PARAMETER param1
    # //this param1 PARAMETER is used as a -local- VARIABLE
    # //throughout the =myFunction= FUNCTION-BODY
    return param1
    # //End of FUNCTION-BODY
end

You have defined a myFunction function
which takes 1 parameter param1
this param1 parameter is used
as a variable throughout the =myFunction= FUNCTION-BODY.

If you want to call/execute this myFunction function
and this myFunction function was defined
as having 1 parameter param1
you will have to provide 1 argument
in our case a "number VALUE" 4

myFunction( 4 )

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

============================================

As you are using the return-statement in your myFunction function
you will only get a return-value no-display.
You can however capture this return-value in a variable
and then use the print-method to do a display.

theResult = myFunction( 4 )
print theResult

OR directly

print myFunction( 4 )

http://stackoverflow.com/questions/5018633/what-is-the-difference-between-print-and-puts


#3

@epiccoolness

With
def shut_down(s):
you are defining a shutdown() function which takes 1 parameter s

This s parameter is used as a =local= variable in your =function-body=

Thus in the IF condition you should be comparing
s against "yes" using the comparison operator ==
like

if s == "yes"

OR
in your ELSIF condition you should be comparing
s against "no" using the comparison operator ==
like

elsif s == "no"

Thus

if _condition_
elsif _condition_
else
end

#4

thanks dude
i get it now

:grinning: :grinning: :grinning: :grinning: :grinning: :grinning: :grinning: :grinning: