# Invalid Syntax - Play it Sam

#1

<Below this line, add a link to the EXACT exercise that you are stuck at.>

<In what way does your code behave incorrectly? Include ALL error messages.>
I cannot see what is wrong with my syntax here.
File “python”, line 37
elif (board[guess_row][guess_col] == “X”):
^
SyntaxError: invalid syntax

<What do you expect to happen instead?>
run normally

```python
``````from random import randint

board = []

for x in range(0, 5):
board.append(["O"] * 5)

def print_board(board):
for row in board:
print " ".join(row)

print_board(board)

def random_row(board):
return randint(0, len(board) - 1)

def random_col(board):
return randint(0, len(board[0]) - 1)

ship_row = random_row(board)
ship_col = random_col(board)
print ship_row
print ship_col

# Everything from here on should be in your for loop
# don't forget to properly indent!
for turn in range(4):
guess_row = int(raw_input("Guess Row: "))
guess_col = int(raw_input("Guess Col: "))

if guess_row == ship_row and guess_col == ship_col:
print "Congratulations! You sank my battleship!"
else:
if guess_row not in range(5) or \
guess_col not in range(5):
print "Oops, that's not even in the ocean."
elif (board[guess_row][guess_col] == "X"):
print( "You guessed that one already." )
else:
print "You missed my battleship!"
board[guess_row][guess_col] = "X"
print_board(board)
# print turn + 1 here
print "Turn",turn + 1
``````
``<do not remove the three backticks above>``

#2

you can have an `elif` after an else, the order is always:

``````if
elif
else
``````

i think you need to look at your indent, the `if not in range`, `elif already guessed` and `else you missed` should have the same indent level

#3

Thanks, seemed like it was an indentation error. changing it to

``````for turn in range(4):
guess_row = int(raw_input("Guess Row: "))
guess_col = int(raw_input("Guess Col: "))

if guess_row == ship_row and guess_col == ship_col:
print "Congratulations! You sank my battleship!"
else:
if guess_row not in range(5) or guess_col not in range(5):
print "Oops, that's not even in the ocean."
elif (board[guess_row][guess_col] == "X"):
print( "You guessed that one already." )
else:
print "You missed my battleship!"
board[guess_row][guess_col] = "X"
print_board(board)
# print turn + 1 here
print "Turn",turn + 1
``````

got it working perfectly

#4

seems you got it

so we have if an else to determine hit and miss:

``````	if guess_row == ship_row and guess_col == ship_col:
print "Congratulations! You sank my battleship!"
else:
# handle different misses here
``````

then we have an if, elif and else to handle the different scenarios for missing, its also important to understand design of this program

#6

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