Introduction to Functions in JS > Functions & if / else


#1



I have completed all the lessons in Javascript section till this one(Introduction to Functions in JS > Functions & if / else). In this lesson they tell to write a function called sleepCheck. Where if the variable numHours has a value greater than or equal to 8 then print something and if less then print something else. My program seems 100% ok. It prints the correct statements upon the use of the function. But still gives me error:
Oops, try again. It looks like sleepCheck() isn't returning "You're getting plenty of sleep! Maybe even too much!" when numHours is 10. Check your if / else syntax and whether you're using the correct comparison operator.
But it actually returns "You're getting plenty of sleep! Maybe even too much!" when numHours is 10. So what's wrong?


var sleepCheck = function(numHours){
    if(numHours >= 8){
        console.log("You're getting plenty of sleep! Maybe even too much!");
    }
    else{
        console.log("Get some more shut eye!");    
    }
    
}

sleepCheck(10);
sleepCheck(5);
sleepCheck(8);


#2

@a_beer,
The Oops-message is mentioning returning
therewith giving the indication that will have to use the return statement
instead of you using the console.log() Method....

the FUNCTION talk

var myFunc = function( param1, param2) {
       //Begin of  anonymous FUNCTION-BODY
       //VARIABLE -myFunc- has an -anonymous function- assigned
       //this -anonymous function- has 2 PARAMETERS param1 and param2
       //param1 and param2 PARAMETERS are used 
       //as -local- VARIABLES throughout the FUNCTION-BODY

      console.log( param1 + " and " + param2 ) ;

      //End of anonymous FUNCTION-BODY
};

If you want to call/execute the anonymous function
you will have to add a pair of parentheses to the variable myFunc
like
myFunc();
As the anonymous function was defined
as having 2 parameters
you have to provide 2 arguments
in our case 2 string VALUES "Alena" and "Lauren"
like
myFunc("Alena","Lauren");

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++

function with 1 parameter using return-statement

var myFunction = function( param1 ) {
       //Begin of FUNCTION-BODY
       //myFunction =function= has 1 PARAMETER param1
       //this param1 PARAMETER is used as a -local- VARIABLE
       //throughout the FUNCTION-BODY

      return param1;

      //End of FUNCTION-BODY
      };

you have defined a myFunction function
which takes 1 parameter param1
this param1 parameter is used
as a variable throughout the FUNCTION-BODY.

If you want to call/execute this myFunction function
and this myFunction function was defined
as having 1 parameter param1
you will have to provide 1 argument
in our case a "number VALUE" 4
myFunction( 4 );

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

============================================

As you are using the return-statement in your myFunction function
you will only get a return-value no-display.
You can however capture this return-value in a variable
and then use the console.log()-method to do a display.

var theResult = myFunction( 4 );
console.log( theResult );

OR directly

console.log( myFunction( 4 ) );

#3

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