Interpreter showing correct result (B) but still error message


#1



https://www.codecademy.com/courses/python-beginner-en-qzsCL/1/3?curriculum_id=4f89dab3d788890003000096#


it keeps telling me that " Oops, try again. get_letter_grade(80) returned 'C' instead of 'B' as expected." while i already get B in my intrepreter with my code


i expect no error since it return B already in the intrepreter. i get frustated while the error message kept saying the result is C


Replace this line with your code. 
lloyd = {
    "name": "Lloyd",
    "homework": [90.0, 97.0, 75.0, 92.0],
    "quizzes": [88.0, 40.0, 94.0],
    "tests": [75.0, 90.0]
}
alice = {
    "name": "Alice",
    "homework": [100.0, 92.0, 98.0, 100.0],
    "quizzes": [82.0, 83.0, 91.0],
    "tests": [89.0, 97.0]
}
tyler = {
    "name": "Tyler",
    "homework": [0.0, 87.0, 75.0, 22.0],
    "quizzes": [0.0, 75.0, 78.0],
    "tests": [100.0, 100.0]
}

# Add your function below!
def average(numbers):
    total=sum(numbers)
    total=float(total)
    return float(total/len(numbers))

def get_average(student):
    homework=average(student["homework"])
    quizzess=average(student["quizzes"])
    test=average(student["tests"])
    return float(0.1*homework+0.3*quizzess+0.6*test)

def get_letter_grade(score):
    if score>=90:
        return "A"
    elif score>80:
        return "B"
    elif score>70:
        return "C"
    elif score>60:
        return "D"
    else:
        return "F"
   
print get_letter_grade(get_average(lloyd))


#2

this line:

elif score>80:

if the number is bigger/greater then 80, return B. But 80 itself is not included, while it should be. use >=, then 80 is included


#3

it works like a charm now.. thank you very much.. spend hours on this scratching head.. and now i can sleep peacefully